+0  
 
0
1248
5
avatar+53 

Find x such that 

\(​​​​​​\lfloor x \rfloor \cdot x = 70\)

express x as a decimal.

 Jun 19, 2018
edited by cormier123  Jun 19, 2018
edited by cormier123  Jun 19, 2018
 #1
avatar+6 
+1

HEY CORMIER(123)! i'll be glad to answer. assuming that those weird bracket thingy mean absolulet valuve, you can assume that x has to be positive. then, that means (x)^2=70, which acordding to my caculator, its bout 8.36. HOPE THIS HELPED!

 Jun 19, 2018
 #2
avatar+6 
+1

PS, tell me if im wrong, and if it's AoPS, paste answer herre. -LUNAMORT 4 LIFE or Purely Slytherin

 Jun 19, 2018
 #3
avatar+53 
+1

Hi, \(​​​​​​\lfloor x \rfloor\) that doesn't represent aboslute value, it denotes the greatest integer that is less than or equal to x, otherwise called the "Greatest integer function."

cormier123  Jun 19, 2018
 #4
avatar+9479 
+2

I don't know the correct way to solve this, but first I guessed that x is 8 point something,

 

which makes  floor(x) = 8

 

And   70 / 8  =  8.75    , so this works:       \( ​​​​​​\lfloor 8.75 \rfloor \cdot 8.75 = 70 \)            smiley

 Jun 20, 2018
 #5
avatar+49 
+1

cormier is right. the weird absolute value thing is NOT absolute value, it represents the greatest integer less than or equal to x. so yeah, thus x would be 8.75

 Jun 20, 2018
edited by kevbamboo  Jun 20, 2018

3 Online Users