+0  
 
0
55
5
avatar+21 

Find x such that 

\(​​​​​​\lfloor x \rfloor \cdot x = 70\)

express x as a decimal.

cormier123  Jun 19, 2018
edited by cormier123  Jun 19, 2018
edited by cormier123  Jun 19, 2018
 #1
avatar+6 
+1

HEY CORMIER(123)! i'll be glad to answer. assuming that those weird bracket thingy mean absolulet valuve, you can assume that x has to be positive. then, that means (x)^2=70, which acordding to my caculator, its bout 8.36. HOPE THIS HELPED!

LUNAMORT  Jun 19, 2018
 #2
avatar+6 
+1

PS, tell me if im wrong, and if it's AoPS, paste answer herre. -LUNAMORT 4 LIFE or Purely Slytherin

LUNAMORT  Jun 19, 2018
 #3
avatar+21 
+1

Hi, \(​​​​​​\lfloor x \rfloor\) that doesn't represent aboslute value, it denotes the greatest integer that is less than or equal to x, otherwise called the "Greatest integer function."

cormier123  Jun 19, 2018
 #4
avatar+7155 
+2

I don't know the correct way to solve this, but first I guessed that x is 8 point something,

 

which makes  floor(x) = 8

 

And   70 / 8  =  8.75    , so this works:       \( ​​​​​​\lfloor 8.75 \rfloor \cdot 8.75 = 70 \)            smiley

hectictar  Jun 20, 2018
 #5
avatar+48 
+1

cormier is right. the weird absolute value thing is NOT absolute value, it represents the greatest integer less than or equal to x. so yeah, thus x would be 8.75

kevbamboo  Jun 20, 2018
edited by kevbamboo  Jun 20, 2018

14 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.