If a haystack in the shape of a right circular cone has a base radius of 5 meters and contains 12 tons of hay, what will be the number of tons of hay in a similar conical haystack whose base diameter is 15 meters? Two right cones are similar if their heights and their base radii are in proportion. Express your answer as a decimal to the nearest tenth.
Base radius $\frac{15}{2}$, multiplying by $\frac{3}{2}$, so height is $12\cdot \frac32=18$.
The volume of a cone is $\pi r^2 \cdot \frac{h}{3}=\pi \cdot \frac{225}{4}\cdot 6=\boxed{\frac{675}{2}\pi}$
Rounded to the nearest tenth it is $\boxed{1060.3}$