+0  
 
0
217
2
avatar

f(x) = In((3x-4)3)

f(x) = In((3x-4)*(3x-4)*(3x-4))

f(x) = In(3x-4) + In(3x-4) + In(3x-4)

f'(x) = 1/(3x-4) + 1/(3x-4) + 1/(3x-4)

f'(x) = 3/(3x-4)

 

I'd assume this was correct, but it isn't. I know how to work it out, but I don't understand why this method doesn't work. 

 

Someone explain.

 

Thanks.

Guest Aug 4, 2017
 #1
avatar
0

Your mistake is in the second last line as the derivative of

log(3x-4) is 3/(3x-4)

Guest Aug 4, 2017
 #2
avatar
0

I see now. Thanks.

Guest Aug 4, 2017

17 Online Users

avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.