f(x) = In((3x-4)^{3})

f(x) = In((3x-4)*(3x-4)*(3x-4))

f(x) = In(3x-4) + In(3x-4) + In(3x-4)

f'(x) = 1/(3x-4) + 1/(3x-4) + 1/(3x-4)

f'(x) = 3/(3x-4)

I'd assume this was correct, but it isn't. I know how to work it out, but I don't understand why this method doesn't work.

Someone explain.

Thanks.

Guest Aug 4, 2017