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# confused

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What is the probability that someone random guesses the correct combination in one attempt if the lock has 3 wheels numbered 0-9

Guest May 24, 2017

#2
+85643
+1

Sorry MG....that's not quite correct....

Assuming that any digit can be repeated.....

We have 10 ways to choose a value in each position.....so the total number of possible combinations =

(10) (10) (10)   =  10^3   = 1000

So....the chances that you guess the correct combination one one try =  1 / 1000  = .001  = .1%

CPhill  May 24, 2017
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#1
+80
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Well, there are only 27 possibillities, so, hmm... maybe a

3.7037037037 percentage?(703703703703703 repeating)

Once again, please correct me if I'm wrong.

mathguardian23  May 24, 2017
edited by mathguardian23  May 24, 2017
#2
+85643
+1

Sorry MG....that's not quite correct....

Assuming that any digit can be repeated.....

We have 10 ways to choose a value in each position.....so the total number of possible combinations =

(10) (10) (10)   =  10^3   = 1000

So....the chances that you guess the correct combination one one try =  1 / 1000  = .001  = .1%

CPhill  May 24, 2017

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