What is the probability that someone random guesses the correct combination in one attempt if the lock has 3 wheels numbered 0-9

Guest May 24, 2017

#2**+1 **

Sorry MG....that's not quite correct....

Assuming that any digit can be repeated.....

We have 10 ways to choose a value in each position.....so the total number of possible combinations =

(10) (10) (10) = 10^3 = 1000

So....the chances that you guess the correct combination one one try = 1 / 1000 = .001 = .1%

CPhill
May 24, 2017

#1**0 **

Well, there are only 27 possibillities, so, hmm... maybe a

3.7037037037 percentage?(703703703703703 repeating)

Once again, please correct me if I'm wrong.

mathguardian23
May 24, 2017

#2**+1 **

Best Answer

Sorry MG....that's not quite correct....

Assuming that any digit can be repeated.....

We have 10 ways to choose a value in each position.....so the total number of possible combinations =

(10) (10) (10) = 10^3 = 1000

So....the chances that you guess the correct combination one one try = 1 / 1000 = .001 = .1%

CPhill
May 24, 2017