Confusing

( √2 , 1)  ( √3 , 2)

Distance

sqrt [ ( √3 - √2)^2  + (2 -1)^2 ]  =

sqrt [ 3 - 2√6 + 2 + 1 ]  =

sqrt  [ 6 - 2√6 ]  =  about  1.049 units

Midpoint

 [ ( √3 + √2 ) / 2  ,  (2 + 1) / 2 ]  =

[ ( √3 + √2 ) / 2 ,  3 / 2 ]      [this is exact, Spawn ...!!!  ]

This page requires the assistance of Knight Melody of the radian table. I need urgent response if I am to get a good grade. Knight CPhill will also be most helpful here.

I know the distance formula and how to use it. I just got confused with the radicals. To foil or not to foil?

( √2 , 1)  ( √3 , 2)

Distance

sqrt [ ( √3 - √2)^2  + (2 -1)^2 ]  =

Notice,Spawn    ( √3 - √2)^2   =   ( √3 - √2) * ( √3 - √2)  =

√3*√3 - 2√3*√2  + √2 *√2    =

3   - 2√6  + 2 

So we have.....

sqrt [ 3 - 2√6 + 2 + 1 ]  =

sqrt  [ 6 - 2√6 ]  =  about  1.049 units

Midpoint

 [ ( √3 + √2 ) / 2  ,  (2 + 1) / 2 ]  =

[ ( √3 + √2 ) / 2 ,  3 / 2 ]      [this is exact, Spawn ...!!!  ]

Thanks, Spawn....

AND I AM ONE OF THOSE MIGHTY KNIGHTS!!!!!