the product of two consecutive integers is 5 more than three times the larger integer. Find the larger integer.
x(x+1) = 3(x+1)+5
x^2 + x = 3x + 8
x^2 - 2x - 8.
(x-4)(x+2)
x = 4, x = -2
But testing, x = -2 doesn't work, so x = 4.
4+1 = 5
The larger number is 5.
I hope this helped. :))
=^._.^=
x = larger x-1 = smaller
x (x-1) = 5 + 3x
x^2 -x = 5+3x
x^2 -4x-5=0
(x-5)(x+1) = 0 x = 5 or -1 then smaller is 4 or -2 5 and 4 or -1 and -2