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Consider a particle following the parametric equations
 

as well as points \(P_1, P_2, P_3\)and\(P_4\)

Say that our particle is at \(P_1 \) at time \(t_1 \)our particle is at \(P_2\) at time \(t_2\), our particle is at \(P_3\) at time \(t_3\), etc.

Enter times \(t_1, t_2, t_3, t_4\) in that order. 

 Jul 27, 2021
 #1
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It's not that hard, I'll do the first one for you. $P_1$ has x value 1, y value 2, so $2t+1=1, 3t+2=2\to t_1=0$.

 Jul 27, 2021
edited by thedudemanguyperson  Jul 27, 2021

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