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# Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis. What is the

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Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis. What is the x component v⃗ x of v⃗ ?

Guest Jul 3, 2014

#1
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60 degrees above the negative x axis means that we are in quadrant 2 so our x component will be negative.  TO find the x component we use the cosine function as it represents x values.  Our calculation looks like

V_x=12cos60=6

jboy314  Jul 3, 2014
#1
+576
+5

60 degrees above the negative x axis means that we are in quadrant 2 so our x component will be negative.  TO find the x component we use the cosine function as it represents x values.  Our calculation looks like

V_x=12cos60=6

jboy314  Jul 3, 2014
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$$\begin{array}{rll} cos60^0&=&\frac{\dot{x}}{12}\\\\ \dot{x}&=&12\times \frac{-1}{2}\\\\ &=&\:-6m/s \end{array}$$

It can  be seen from the diagram that the velocity in the x direction must be negative.

Melody  Jul 5, 2014