Thank you! (For (d) you don't have to graph it on a coordinate plane if it's too inconvenient, please just explain where I need to graph!)
Hello!
You can graph it out with desmos. https://www.desmos.com
x intercepts are when y = 0, when y = 0, the x coordinates are -4 and 1.
y intercepts are when x = 0, which is 4.
https://www.varsitytutors.com/hotmath/hotmath_help/topics/axis-of-symmetry-of-a-parabola
Try to see if you can find the vertex and axis by yourself. :))
You can also see by graphing it in desmos.
=^._.^=
Hi Cordueroy, catmg has given you a good answer but I am happy to discuss it with you.
This question is poorly written because the formula has f(x) but you are asked for y.
You just need to understand that y=f(x)
\(f(x)=-(x+4)(x-1)\)
Think about the y axis, what are some points on the y axis?
(0,6), (0,-2) (0,7) .... etc, What do they all have in common? well the x value is always 0.
SO, the equation of the y axis is x=0
So to find the y intercept, that is where it crosses the y axis, you must solve the equation simultaneously with x=0.
that might sound complicated but it is not.
Just substitute the x in the equation with 0, like this
\(f(0)=-(0+4)(0-1)\\ f(0)=-+4*-1\\ f(0)=+4 \)
So the y intercept (which should really be called the f(x) intercept) is 4
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the x axis has the equation y=0 f(x)=0
To find the x intercept you have to solve
\(0=-(x+4)(x-1)\)
Two terms will only multiply to give 0 if one or both of them is equal to 0 so
either
\(x+4=0\quad \rightarrow \quad x=-4\\or\\ x-1=0\quad \rightarrow \quad x=+1\)
so the x intercepts are -4 and 1
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This is a concave down parabola.
I know that it is a parabola because the highest power of x, if you multiply it out is 2 (x^2)
And I know it is concave down because it will because the leading coefficient is neg (-x^2)
The axis of symmetry for a parabola, concave up or down, is half way between the two x intercepts
\(x=\frac{-4+1}{2}=\frac{-3}{2}=-1.5\)
The equation of the axis of symmetry is x = -1.5
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To find the vertex, substitute x=-1.5 into the formula to find the y value.
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And as catmg already suggested, use Desmos to graph it.