+598 1. Given that z is a standard Normal random variable, find the following probabilities: (6 Points)
a. P(z <0.52)
b. P(z > -0.63)
c. P(-0.31<z<1.345)
Any help with calculations would be greatly appreciated - thanks very much.
+23252 Are you using a table or a calculator?
If you are using a TI-84+ calculator, press (2nd) (DISTR) and 2:normalcdf(
To find P(z<0.52), you can used normalcdf(-100,0.52) to get . 0.698.
To find P(z>-0.63), you can use normalcdf(-0.63,100) to get 0.736.
To find P(-0.31<z<1.345), you can use normalcdf(-0.31,1.345) to get 0.529.
(The answers are rounded.)
You needn't use -100 for the left-hand limit or 100 for the right-hand limit, but you should use numbers <-6 or >+6 for the limits.
