A hollow cylinder, closed at both ends, has a volume of 250.0mL and contains 4.60g of argon gas. A 90.0g cube of sodium (density = 970.0 g/L) is inserted into the tube in such a way that no gas escapes. What is the density of the gas afterwards??
Please write full equation. (# of...)
+33657
Note that density = mass/volume.
The volume occupied by the sodium is Vsodium = 90/970 L = 1000*90/970 mL or 92.78mL.
This reduces the volume available for the gas, so its new density = 4.6/(250 - 92.78) g/mL
4.6(250−92.78)=2307861=0.0292583640758173
new density ≈ 0.029 g/mL
.
+33657
Note that density = mass/volume.
The volume occupied by the sodium is Vsodium = 90/970 L = 1000*90/970 mL or 92.78mL.
This reduces the volume available for the gas, so its new density = 4.6/(250 - 92.78) g/mL
4.6(250−92.78)=2307861=0.0292583640758173
new density ≈ 0.029 g/mL
.
