+50 I have found two solutions to my problem in polar coordinates, but have to submit them to Cartesian coordinate form. How do I convert them?
Point \(A = (2,\frac{\pi}{3})\)
Point \(B = (4,\frac{11\pi}{6})\)
+1632 (r, theta) in polar form, where theta indicates the direction and r, the length. Think of (2, pi/3) as a triangle with diagonal two and angle pi/3 = 60 degrees.
Thus, the base of the triangle, is 2/2 = 1, and then the height would be sqrt(3), so Point A has coordinates (1, sqrt(3)).
Point B likewise, in the fourth quadrant, would have the included angle be 30 degrees with a diagonal of 4. Thus, its coordinates would be (2sqrt(3), -2).
