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# converting to vertex form?

+1
286
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\({h^2 + 2h + 5} = 0\) and please show step by step please :)

Feb 13, 2018

#1
+7598
+3

h2 + 2h + 5   =   0

First subtract  5  from both sides of the equation.

h2 + 2h   =   0 - 5

Now we want to add a number to both sides that will cause the left side of the equation to be a perfect square trinomial. So add  (2/2)2  , which is  1 ,  to both sides of the equation.

h2 + 2h + 1   =   0 - 5 + 1

h2 + 2h + 1   =   -4

Now that the left side is a perfect square trinomial, it factors like this...

(h + 1)2   =   -4

And we can add  4  to both sides so the right side  =  0  again.

(h + 1)2 + 4   =   0

The question didn't say to solve for  h , it just said convert to vertex form...I think that is it.

Feb 13, 2018

#1
+7598
+3

h2 + 2h + 5   =   0

First subtract  5  from both sides of the equation.

h2 + 2h   =   0 - 5

Now we want to add a number to both sides that will cause the left side of the equation to be a perfect square trinomial. So add  (2/2)2  , which is  1 ,  to both sides of the equation.

h2 + 2h + 1   =   0 - 5 + 1

h2 + 2h + 1   =   -4

Now that the left side is a perfect square trinomial, it factors like this...

(h + 1)2   =   -4

And we can add  4  to both sides so the right side  =  0  again.

(h + 1)2 + 4   =   0

The question didn't say to solve for  h , it just said convert to vertex form...I think that is it.

hectictar Feb 13, 2018