h2 + 2h + 5 = 0
First subtract 5 from both sides of the equation.
h2 + 2h = 0 - 5
Now we want to add a number to both sides that will cause the left side of the equation to be a perfect square trinomial. So add (2/2)2 , which is 1 , to both sides of the equation.
h2 + 2h + 1 = 0 - 5 + 1
h2 + 2h + 1 = -4
Now that the left side is a perfect square trinomial, it factors like this...
(h + 1)2 = -4
And we can add 4 to both sides so the right side = 0 again.
(h + 1)2 + 4 = 0
The question didn't say to solve for h , it just said convert to vertex form...I think that is it.
h2 + 2h + 5 = 0
First subtract 5 from both sides of the equation.
h2 + 2h = 0 - 5
Now we want to add a number to both sides that will cause the left side of the equation to be a perfect square trinomial. So add (2/2)2 , which is 1 , to both sides of the equation.
h2 + 2h + 1 = 0 - 5 + 1
h2 + 2h + 1 = -4
Now that the left side is a perfect square trinomial, it factors like this...
(h + 1)2 = -4
And we can add 4 to both sides so the right side = 0 again.
(h + 1)2 + 4 = 0
The question didn't say to solve for h , it just said convert to vertex form...I think that is it.