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Hello!

 

Show that for all perfect squares \(n\) such that we can express:

 

\(n = a^{2z}\),

with \(a\), an integer and \(z\), the number of factors of \(n\).

 

How do you solve this?

 

Thanks, and enjoy!

 Mar 13, 2022
edited by jsaddern  Mar 13, 2022
 #1
avatar+2401 
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I'm not sure I understand this question properly. 

If n = 4, then z = 3. 

So there must exist an interger a such at 4 = a^6. 

I don't think an integer a exists.

Am I interpreting the problem wrong?

 

=^._.^=

 Mar 13, 2022
 #2
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I didn't understand the question either.

Melody  Mar 13, 2022

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