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avatar+776 

look what the calculator gave me!

I put in:

\(f(x)=x^2+{x\over\pi}-e^x\)

and it gave me:

\(f(x)=x^2+{x\over\pi}-e^x\Rightarrow \begin{bmatrix} x=-(((\sqrt{(4*\pi)*f(x)+(\pi^2)-{((4*e^x)*\pi))+\pi)\over2}} \\ x=((\sqrt{(4*\pi)*f(x)+(\pi^2)-{((4*e^x)*\pi))-\pi)\over2}} \end{bmatrix}\)

 Apr 10, 2016
 #1
avatar+9673 
0

Your calculator is trying to obtain a general solution of x of your equation

 Apr 11, 2016
 #2
avatar+776 
0

I know, I just wanted to show evreyone the cool output.

User101  Apr 13, 2016

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