look what the calculator gave me!
I put in:
f(x)=x2+xπ−ex
and it gave me:
f(x)=x2+xπ−ex⇒[x=−(((√(4∗π)∗f(x)+(π2)−((4∗ex)∗π))+π)2x=((√(4∗π)∗f(x)+(π2)−((4∗ex)∗π))−π)2]
Your calculator is trying to obtain a general solution of x of your equation
I know, I just wanted to show evreyone the cool output.