What is the area of the triangle formed by the lines 5x-2y=10,3x+4y=12 and x-axis?
We have drawn two lines 5x-2y=10, 3x+4y=12 on the graph.
We got two three points which forms triangle A, B, C.
A is at y= 0 on line 5x-2y=10,
= > 5x=10
=> x = 2
Now, B is on line 3x+4y=12 , at y=0 ,
=> x = 4
Then, C is at point of intersection of both lines 3x+4y=12 and 5x-2y=10.
That is, Using Elimination method,
Substituting in any line out of two, we get y = 15/13 .
Hence, Area of triangle is 15/13 sq. units.
(By the way this is someone else's answer, not mine. I do not take credit for the detailed explanation.)
Hope this helped!