+0  
 
0
65
2
avatar

The circle centered at (2,-1) and with radius 4 intersects the circle centered at (2,5) and with radius sqrt(17) at two points A and B.  Find (AB)^2.

 Jun 14, 2021
 #1
avatar
0

The circle centered at (2,-1) and with radius 4 intersects the circle centered at (2,5) and with radius sqrt(17) at two points A and B.  Find (AB)2.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Center C = (2, -1)         center D = (2, 5)           CD = 6

 

AC = 4          AD = √17

 

AB and CD intersect at point N           

 

CN = x          DN = 6 - x

 

x / 4 = (6 - x) / √17          x = - 24(4 - √17) = 2.954535015

 

(AB)2 = (2x)2

 Jun 15, 2021
 #2
avatar
0

corrections: the equation in blue ink is incorrect!!! cheeky

 

sqrt(42 - x2) = sqrt[17 - (6 - x)2]        x = 35/12

 

(AB)2 = (2x)2

 

civonamzuk laugh

Guest Jun 15, 2021

27 Online Users

avatar
avatar