A triangular region is bounded by the two coordinate axes and the line given by the equation 2x + y = 8 . What is the area of the region, in square units?
+36916 This is a right triangle and you need to find the x-axis and y-axis intercepts
when y = 0 x -axis intercept becomes 2x + 0 = 8 x axis intercept = 4
when x = 0 y -axis intercept is computed as 2(0) + y = 8 y -axis intercept = 8
so you have a right triangle with legs of 4 and 8 (these are the base and height of the triangle )
area = 1/2 b * h
= 1/2 4 * 8 = 16 units2
+36916 This is a right triangle and you need to find the x-axis and y-axis intercepts
when y = 0 x -axis intercept becomes 2x + 0 = 8 x axis intercept = 4
when x = 0 y -axis intercept is computed as 2(0) + y = 8 y -axis intercept = 8
so you have a right triangle with legs of 4 and 8 (these are the base and height of the triangle )
area = 1/2 b * h
= 1/2 4 * 8 = 16 units2
