Find the area of the region satisfying the inequality x^2 + y^2 <= 4x + 6y + 18.
x^2 + y^2 <= 4x + 6y + 18. re-arrange into circle equation form
x^2 -4x + y^2-6y < = 18 complete the square for x and y
(x-2)^2 + (y-3)^2 < = 18 + 4 + 9 this is a circle with center 2,3 and radius sqrt(31)
Area of circle with radius sqrt(31) <====== can you calculate that?