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What is the x-coordinate of the point on the x-axis that is equidistant from points A(2,0) and B(0,6)?

 Aug 10, 2021
 #1
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midpoint = ((x1 + x2) / 2, (y1 + y2) / 2) = (1, 3)

So the answer is 1

 Aug 10, 2021
 #2
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What is the x-coordinate of the point on the x-axis that is equidistant from points A(2,0) and B(0,6)?

 

Hello Guest!

 

The distance of the point on the x-axis from the origin is x.

Then the following applies:

\(-x+2=\sqrt{x^2+6^2}\ |\ square \\ x^2-4x+4=x^2+36\\ -4x=32 \)

\(x=-8\)

The x-coordinate of the point on the x-axis is -8.

laugh  !

 Aug 10, 2021

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