The circle centered at (2, -1) and with radius 4 intersects the circle centered at (2, 5) and with radius sqrt(10) at two points A and B. Find (AB)^2.
Find ¯AB 2
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+√16−(x−2)2−1=−√10−(x−2)2+5+√16−(x−2)2+√10−(x−2)2=6 | square16−(x−2)2+2⋅√16−(x−2)2⋅√10−(x−2)2+10−(x−2)2=36
x∈{2−√152,2+√152}
¯AB 2=15
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