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The center of the circle with equation x^2+y^2=4x-12y-39 is the point (h,k). What is h+k?

 Jun 22, 2021

Best Answer 

 #1
avatar+33360 
+2

x^2 - 4x      +     y^2 - 12y         = - 39      complete the square for x and y

(x-2)^2            + (y-6)^2          = -39 + 4 + 36

 

 

(h, k) = (2,6)   .....     you can complete the answer .....

 Jun 22, 2021
 #1
avatar+33360 
+2
Best Answer

x^2 - 4x      +     y^2 - 12y         = - 39      complete the square for x and y

(x-2)^2            + (y-6)^2          = -39 + 4 + 36

 

 

(h, k) = (2,6)   .....     you can complete the answer .....

ElectricPavlov Jun 22, 2021

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