The center of the circle with equation x^2+y^2=4x-12y-39 is the point (h,k). What is h+k?
+37146 x^2 - 4x + y^2 - 12y = - 39 complete the square for x and y
(x-2)^2 + (y-6)^2 = -39 + 4 + 36
(h, k) = (2,6) ..... you can complete the answer .....
+37146 x^2 - 4x + y^2 - 12y = - 39 complete the square for x and y
(x-2)^2 + (y-6)^2 = -39 + 4 + 36
(h, k) = (2,6) ..... you can complete the answer .....
