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A triangle has vertices at coordinates (1,2), (-7,10) and (1,-12). What is the number of units in the length of the shortest side of the triangle?

 Jan 28, 2021
 #1
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8 √2

 Jan 28, 2021
 #2
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Longest leg is between -7,10   and   1, -12

distance formula     (-7-1)^2 + (10- -12)^2 = d^2

                                  64      +     484 = d^2                        d = 23.4 units

 

Uhhhh.....

SHORTEST side is between

1,2   and   -7,10

  Using the same distance formula

      d = sqrt ( 64 + 64) = 11.3 units       or    sqrt 128   = 8 sqrt 2    as Guest #1 posted without explanation.

 Jan 28, 2021

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