A triangle has vertices at coordinates (1,2), (-7,10) and (1,-12). What is the number of units in the length of the shortest side of the triangle?
Longest leg is between -7,10 and 1, -12
distance formula (-7-1)^2 + (10- -12)^2 = d^2
64 + 484 = d^2 d = 23.4 units
Uhhhh.....
SHORTEST side is between
1,2 and -7,10
Using the same distance formula
d = sqrt ( 64 + 64) = 11.3 units or sqrt 128 = 8 sqrt 2 as Guest #1 posted without explanation.
