The points (1,-2) and (4,-10) are adjacent vertices of a square. What is the perimeter of the square?
To find the perimeter, we must first find the distance from (1, -2) to (4, -10). To do this, we can use the distance formula.
√((xδ)2+(yδ)2), where δ=the change in positioning for the point.
We can plug in for this equation to get √((4−1)2+(−10−−2)2)
Simplifying this, we get √(32+(−8)2), then √(9+64), and finally √73
Since there are 4 sides to a square, multiply √73 by 4 to account for all sides.
The final answer should be 4√73 since 73 is prime.