The points (1,-2) and (4,-10) are adjacent vertices of a square. What is the perimeter of the square?
+76 To find the perimeter, we must first find the distance from (1, -2) to (4, -10). To do this, we can use the distance formula.
\(\sqrt((x\delta)^2+(y\delta)^2),\) where \(\delta\)=the change in positioning for the point.
We can plug in for this equation to get \(\sqrt((4-1)^2+(-10--2)^2)\)
Simplifying this, we get \(\sqrt(3^2+(-8)^2)\), then \(\sqrt(9+64)\), and finally \(\sqrt73\)
Since there are 4 sides to a square, multiply \(\sqrt73\) by 4 to account for all sides.
The final answer should be \(4\sqrt73\) since 73 is prime.
