A line has slope 2. Find the area of the triangle formed by this line and the coordinate axes, if the distance between the origin and the line is \(8\)
Find the area of the triangle.
Hello Guest!
\(Touch\ Point\ P:\\ x_P=8\cdot cos(atan -\frac{1}{2})=7.155\\ y_P=8\cdot sin(atan -\frac{1}{2})=-3.578\\ f(x) =2\cdot (x-x_P)+y_P\\ f(x)=2x-2\cdot 7.155-3.578\\ f(x)=2x-17.888=0\\ P_x\ (8.944,0)\\ P_y(0,-17.888)\)
The area of this triangle is
\(A_{xy}=\frac{1}{2}\cdot 8.944\cdot (-17.888)\)
\(A_{xy}=-79.995\)
!