Find the equation of the line passing through the points (-2,5) and (3/2, 2). Express the answer in standard form.
+2668 The slope of the line is \({{2 - 5 } \over {1.5+2}} = -{6 \over 7}\)
Plugging this into slope-intercept form, we have: \({35 \over 7} = {12 \over 7} + b\), meaning the y-intercept is \({23 \over 7}\)
Thus, our equation is: \(y = -{6 \over 7}x + {23 \over 7}\)
To convert it to standard form, add \({6 \over 7}x\) to both sides, giving us: \(y + {6 \over 7}x = {23 \over 7}\)
Multiply this by 7, giving us: \(\color{brown}\boxed{7y+6x=23}\)
+2668 The slope of the line is \({{2 - 5 } \over {1.5+2}} = -{6 \over 7}\)
Plugging this into slope-intercept form, we have: \({35 \over 7} = {12 \over 7} + b\), meaning the y-intercept is \({23 \over 7}\)
Thus, our equation is: \(y = -{6 \over 7}x + {23 \over 7}\)
To convert it to standard form, add \({6 \over 7}x\) to both sides, giving us: \(y + {6 \over 7}x = {23 \over 7}\)
Multiply this by 7, giving us: \(\color{brown}\boxed{7y+6x=23}\)
