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In the diagram, the four points have coordinates $A(0,1)$, $B(1,3)$, $C(5,2)$, and $D(4.5,0)$.  What is the area of quadrilateral $ABCD$?

 Jan 15, 2024

Best Answer 

 #1
avatar+36919 
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Here is what I would do: area of red rectangle =   5 x 3 = 15  units^2 

   then subtract each of the right triangles    area = 1/2 b * h 

        15 - 1 - 2 - 1/2  - 2.25  =   9.25 units^2 

 Jan 15, 2024
 #1
avatar+36919 
+1
Best Answer

Here is what I would do: area of red rectangle =   5 x 3 = 15  units^2 

   then subtract each of the right triangles    area = 1/2 b * h 

        15 - 1 - 2 - 1/2  - 2.25  =   9.25 units^2 

ElectricPavlov Jan 15, 2024

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