The circle 2x^2 = -2y^2 + 2x - 4y + 20 is inscribed inside a square which has a pair of sides parallel to the x-axis. What is the area of the square?
+289 The area of the square is 80.
Im sorry that there is no diagram. I cant upload pictures for some reason
+118673 2x^2 = -2y^2 + 2x - 4y + 20
\(2x^2 = -2y^2 + 2x - 4y + 20\\ x^2 = -y^2 + x - 2y + 10\\ (x^2-x)\;\;\;+(y^2 +2y) = 10\\ (x^2-x+0.25)\;\;\;+(y^2 +y+1) = 10+0.25+1\\ (x-0.5)^2\;\;\;+(y+1)^2 = 11.25\\\)
This is a circle with a radius of \(\sqrt{11.25}\)
What will the diameter be?
So what is the area of the square that circumscribes this circle? Hint: sketch it.
LaTex:
2x^2 = -2y^2 + 2x - 4y + 20\\
x^2 = -y^2 + x - 2y + 10\\
(x^2-x)\;\;\;+(y^2 +2y) = 10\\
(x^2-x+0.25)\;\;\;+(y^2 +y+1) = 10+0.25+1\\
(x-0.5)^2\;\;\;+(y+1)^2 = 11.25\\
