Can you help with this?
What is the area of the region defined by the equation $x^2+y^2 - 7 = 4y-14x+2x-6y+3$?
x^2+y^2 - 7 = 4y-14x+2x-6y+3
Rearrange as
x^2 +12x + y^2 + 2y = 10 complete te square on x,y
x^2 + 12x + 36 + y^2 + 2y + 1 = 10 + 36 + 1
(x + 6)^2 + ( y + 1)^2 = 47
This is a circle centered at ( -6, -1) with a radius of sqrt (47)
The area of the circle = pi * r^2 = pi * ( sqrt 47)^2 = 47 pi