The lines y = 2x and y = 8/3*x are drawn in the coordinate plane. Find the slope of the line that bisects the acute angle between these lines.
I'm not sure if this is correct but I think that it would just the average of the slopes. Which is 7/3.
[arctan(2) + arctan (8/3) ] / 2 = 66.43945
tan (66.43945)= bsector slope =2.2932