cos x*cos 2x. cos 3x
=(2.cosx .cos2x.cos3x)/2
=[2cos^2(3x)+2cos3x.cosx)/4
=(1+cos 6x +cos4x +cos2x)/4
Please explain how this step has come from the previous step!
Thanks in advance.
I think that you have lost me on the step before that Sasini.
(And I am usually pretty good at these)
plz give me those steps. i need them now
I think that you misunderstood me Sasini.
Can you show me how you got the 2nd last step?
+752 
