coshX*cosx=0 x=?

Solve for x over the real numbers:
cos(x) cosh(x) = 0

Split into two equations:
cos(x) = 0 or cosh(x) = 0

Take the inverse cosine of both sides:
x = π/2 + π n for n element Z
 or cosh(x) = 0

cosh(x) = 0 has no solution since for all x element R, cosh(x)>=1 and True:
Answer: | x = π/2 + π n for n element Z

coshx*cosx=0  x=?

$cos\ x =0\\x=\frac{\pi}{2}+\pi\cdot n\\n \in ℤ$

$cosh\ x=\frac{1}{2}(e^x+e^{-x})>0\\ for \ x\in \Re$    no solution

$solution:$

$coshx \cdot cosx=0\\x_1=\frac{\pi}{2} \\x_2=\frac{\pi}{2}+\pi\\x_3=-\frac{\pi}{2}\\x_4=-(\frac{\pi}{2}+\pi)$

$x=\frac{\pi}{2}+\pi\cdot n$     Thank you! C.

$for\ n \in ℤ$

  !

Actually, the guest is correct....this graph is symmetric around the y axis  and will = 0 at

pi/2 + n*pi      radians......where n is an integer.......

See the graph below :