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Cotan Q = tan 21° 25’ 21.02” . cos -7° 20’ 36” : sin 70° 33' 1.75” – sin -7° 20’ 36” . cotan 70° 33' 1.75”

 Oct 7, 2017
 #1
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What do you need done with these angles?

 Oct 7, 2017
 #2
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Cotan Q = tan 21° 25’ 21.02” . cos -7° 20’ 36” : sin 70° 33' 1.75” – sin -7° 20’ 36” . cotan 70° 33' 1.75”

 

What is te colon doing in the middle?

 

I am just playing - I do not even know what you are really wanting from this. I assume you want an exact (or approximate) value for Q?

But the colon makes no sense.

 

 

Let  A= 70° 33' 1.75”

 

Let B =  -7° 20’ 36”

 

Let C =  21° 25’ 21.02”

 

 

Cotan Q = tan C . cosB : sin A – sin B. cotan A

 

 

90+7+20/60+36/3600-70-33/60-1.75/3600 = 26.7928472222222222  that doesnt look helpful

 

Is the colon meant to be a division???

 

\(Cotan Q =( tan C . cosB ) \div ( sin A – sin B. cotan A)\\ Cotan Q =( tan C . cosB ) \div ( sin A – sin B* \frac{cosA}{sinA})\\ Cotan Q =( tan C . cosB ) \div (\frac{ sin ^2A – sin B* cosA}{sinA})\\ Cotan Q =( tan C . cosB ) \times (\frac{sinA}{ sin ^2A – sin B* cosA})\\ Cotan Q =\frac{tan C . cosB.sinA}{ sin ^2A – sin B* cosA}\\ tan Q =\frac{ sin ^2A – sin B* cosA}{tan C . cosB.sinA}\\\)

 

None of that looks very helpful.

 Oct 8, 2017

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