+0

Cotan Q = tan 21 25’ 21.02” . cos -7 20’ 36” : sin 70 33' 1.75” – sin -7 20’ 36” . cotan 70 33' 1.75”

0
575
2

Cotan Q = tan 21° 25’ 21.02” . cos -7° 20’ 36” : sin 70° 33' 1.75” – sin -7° 20’ 36” . cotan 70° 33' 1.75”

Oct 7, 2017

#1
0

What do you need done with these angles?

Oct 7, 2017
#2
+100809
0

Cotan Q = tan 21° 25’ 21.02” . cos -7° 20’ 36” : sin 70° 33' 1.75” – sin -7° 20’ 36” . cotan 70° 33' 1.75”

What is te colon doing in the middle?

I am just playing - I do not even know what you are really wanting from this. I assume you want an exact (or approximate) value for Q?

But the colon makes no sense.

Let  A= 70° 33' 1.75”

Let B =  -7° 20’ 36”

Let C =  21° 25’ 21.02”

Cotan Q = tan C . cosB : sin A – sin B. cotan A

90+7+20/60+36/3600-70-33/60-1.75/3600 = 26.7928472222222222  that doesnt look helpful

Is the colon meant to be a division???

$$Cotan Q =( tan C . cosB ) \div ( sin A – sin B. cotan A)\\ Cotan Q =( tan C . cosB ) \div ( sin A – sin B* \frac{cosA}{sinA})\\ Cotan Q =( tan C . cosB ) \div (\frac{ sin ^2A – sin B* cosA}{sinA})\\ Cotan Q =( tan C . cosB ) \times (\frac{sinA}{ sin ^2A – sin B* cosA})\\ Cotan Q =\frac{tan C . cosB.sinA}{ sin ^2A – sin B* cosA}\\ tan Q =\frac{ sin ^2A – sin B* cosA}{tan C . cosB.sinA}\\$$

None of that looks very helpful.

Oct 8, 2017