#1

#3**+1 **

30 ways i can explain it but my working got deleted when i was writing it

mathisopandcool
Jun 10, 2021

#4**0 **

If **B** is adjacent to** A **we can make them as 1 letter, so **4!=24**

If **B** is one away from **A**, we have **4** cases.

**B**C**A**D

**B**D**A**C

D**B**C**A**

C**B**D**A**

If **B** is two away from** A** we get:

**B**CD**A**

**B**DC**A**

**24+4+2=30**

**30 ways**

mathisopandcool Jun 10, 2021

#6

#7**0 **

You get 24

plus

9

plus

12

plus

6

24+9+12+6

33+18

51 im rlly bad at math idk if this is r

mathisopandcool
Jun 10, 2021

#9**+2 **

Best Answer

This has a really nice method.

B will be left of A 50% of the time, right of A 50% of the time.

5*4*3*2*1 total ways to be in a line, 50% of which are where B is on the left of A.

5*4*3*2*1/2 = 60

=^._.^=

catmg Jun 10, 2021

#11**+2 **

Lets have a look at your method mathisopandcool

XXXXB 4! = 24

XXXBX 3*3! =18

XXBXX 3*2! *2 =12

XBXXX 3! =6

total = 24+18+12+6 = 60 ways

If you want me to explain any of these just ask.

Melody Jun 10, 2021

#13**+3 **

A X X X X Four ways for B to be to the right

X A X X X Three ways

X X A X X Two ways

X X X A X One way total of 10 ways

the other three slots can be filled in 3 * 2 *1 ways = 6 ways for EACH of the 10 possibles

10 * 6 = 60 ways

ElectricPavlov Jun 10, 2021