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Alice, Andrew, and six other students are to be divided into two teams of four people. How many ways are there to form the teams so that Alice and Andrew are on opposite teams?

 Mar 2, 2019
 #1
avatar+101856 
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We only need to consider one of the teams

 

On Alice's team .....we have 6 ways to choose the next person, 5 ways to choose the next one after that and 4 ways to choose the final person

 

So...we have  ( 6 * 5 * 4)  =  120 possible ways of choosing Alice's team  

 

And the other players on each of Andrew's  possible teams are the ones - by default - not chosen for Alice's team

 

So.....120 ways

 

cool cool cool

 Mar 2, 2019
edited by CPhill  Mar 8, 2019
 #2
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I don't think 120 ways is right...

 Mar 8, 2019
 #3
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yeah, i have the same problem and it was not correct

neither is 240

is there 6C3 somewhere?

Guest Mar 10, 2019

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