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How many distinct odd-digit numbers can be written with the digits 1,2,3, 4 and 5 if no digit may be used more than once?

 Jan 2, 2022
 #1
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There are some great explanations out there. Start checking them out before you post an question

https://web2.0calc.com/questions/help_16304 (No credit to me from the link)

 Jan 2, 2022
edited by SmartWater  Jan 2, 2022
 #2
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1, 2, 3, 4, 5 ==5 digits

 

5! ==120 permutations. Each permutation begins with one of the 5 digits this many times: 120 / 5 ==24 permutations. How many odd numers are there?  There are 3 such numbers: 1, 3 and 5.

 

Therefore, the total number of ODD permutations ==3  x  24 ==72 such permutatins.

 Jan 2, 2022

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