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Given the four digits 2, 4, 6, and 7, how many different positive three-digit integers can be formed using these digits if a digit may not be repeated in an integer?

 Apr 28, 2022
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2, 4 , 6, 7

 

We  can  choose  any  3 of 4 =  C(4,3)  =   4

 

This will form 4 different sets  with 3 elements  each  and permuting these =  3!  = 6

 

So

 

4 * 3! =   24  integers

 

cool cool cool

 Apr 28, 2022

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