Find the number of positive integers that satisfy both the following conditions:
- Each digit is a 1 or a 2 or a 3
- The sum of the digits is 5
The positive integers are,
11111, 1112, 1121, 1211, 2111, 221, 212, 122, 311, 131, 113, 32, 23.
So, there are 13 numbers that satisfy the condition.
To find the number of positive integers that satisfy both conditions, we can approach it systematically by considering the possible combinations of digits that sum up to 5. Since each digit can be 1, 2, or 3, and we need to find the combinations that sum up to 5, we can start with the smallest possible digit combinations and incrementally increase them until we reach the sum of 5.
Here are the possible combinations:
(1, 1, 1, 1, 1)
(1, 1, 1, 2)
(1, 1, 2, 1)
(1, 2, 1, 1)
(2, 1, 1, 1)
(1, 1, 3)
(1, 3, 1)
(3, 1, 1)
(1, 2, 2)
(2, 1, 2)
(2, 2, 1)
(2, 3)
(3, 2).