+0  
 
0
11
4
avatar+1351 

Find the number of positive integers that satisfy both the following conditions:
- Each digit is a 1 or a 2 or a 3
- The sum of the digits is 5

 Mar 26, 2024
 #1
avatar+128794 
+1

11111          

1112   1121  1211  2111

122      212    221

113      131    311

 23         32

 

cool cool cool

 Mar 26, 2024
 #2
avatar+15 
+1

The positive integers are, 

11111, 1112, 1121, 1211, 2111, 221, 212, 122, 311, 131, 113, 32, 23.

 

So, there are 13 numbers that satisfy the condition.

 Mar 26, 2024
 #4
avatar+2 
+1

To find the number of positive integers that satisfy both conditions, we can approach it systematically by considering the possible combinations of digits that sum up to 5. Since each digit can be 1, 2, or 3, and we need to find the combinations that sum up to 5, we can start with the smallest possible digit combinations and incrementally increase them until we reach the sum of 5.

Here are the possible combinations:

(1, 1, 1, 1, 1)

(1, 1, 1, 2)

(1, 1, 2, 1)

(1, 2, 1, 1)

(2, 1, 1, 1)

(1, 1, 3)

(1, 3, 1)

(3, 1, 1)

(1, 2, 2)

(2, 1, 2)

(2, 2, 1)

(2, 3)

(3, 2).

 Mar 26, 2024

2 Online Users

avatar
avatar