+0  
 
-1
20
1
avatar+1459 

A standard six-sided die is rolled $7$ times.  You are told that among the rolls, there was one $1,$ one $2$, one $3$, one $4$, one $5$, and two $6$s.  How many possible sequences of rolls could there have been?  (For example, 2, 3, 4, 6, 6, 1, 5 is one possible sequence.)

 Feb 14, 2024
 #1
avatar+129873 
+1

No. of possible identifiable sequences  =   (No. of rolls)!  / ( multiple occurences of any number(s)) ! =

  7!  / 2!  =  2520

 

cool cool cool

 Feb 15, 2024

0 Online Users