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Old MacDonald has 5 chickens, 4 donkeys, and 7 emus. How many ways can he pair up the animals so that every pair consists of animals of different species? (The order of the animals within each pair does not matter, and the order among the pairs does not matter. Assume that all animals are distinguishable.)

 Mar 14, 2021
 #1
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btw: this is the OP, the answer isn't 83...

 Mar 14, 2021
 #2
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There are (4 + 5)(4 + 7)(5 + 7) = 1188 ways of pairing the animals.

 Mar 14, 2021

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