From ten people, how many ways can you form a team of eight people consisting of a project manager, two (equivalent) deputy project managers, and five (equivalent) engineers?
+33 There are 10 ways to pick a project manager
\(\binom{9}{2} = \frac{9 \times 8}{2 \times 1} = 36\) ways to pick two deputy project managers
\(\binom{7}{5} = \binom{7}{2} = \frac{7 \times 6}{2 \times 1} = 21\)ways to pick five engineers
\(10 \times 36 \times 21 = \boxed{7560}\)
