Find the number of six-digit numbers, where the sum of the digits is divisible by 8.
+118609 100 000 to 999 999 is 900 000 numbers altogether
6 numbers that add to 8
The sum will be teween 8 and 54
so the sum could be 8,16,24,32,40,48,
800 000
710 000
620 000
611 000
530 000
521 000
511 100
440 000
432 000
431 100
422 000
421 100
411 110
332 000
331 100
322 100
321 110
311 111
222 200
222 110
221 111
There is an awflu lot to count. I guess there is a better method
970 000
961 000
952 000
951 100
943 000
942 100
941 110
933 100
932 110
931 111
922 210
922 111
...
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The sum of the 6 digits must be between 1 and 54
6 of those are divisable by 8
If they were all equally likely outcomes then the answer would be 6/54. Trouble is they are not all equally likely outcomes.
there are 900 000 sums altogether. Ifthey were equally likely it would be 6/54 * 900 000 = 100 000 but they are not equally likely.
Yea, I don't know. 
