Catherine rolls a 6-sided die six times, and the product of her rolls is \(1200\). How many different sequences of rolls could there have been? (The order of the rolls matters.)

Guest Jun 9, 2022

#1**+1 **

124556 ( 360 ) , 222556 ( 60 ) , 223455 ( 180 ) , 344556 ( 180 ) , >>Total combinations = 4

**>>Totals in parentheses = 780 permutations**

Guest Jun 9, 2022

#2**+1 **

I do not want to do it all for you.

Start by finding the prime factors of 1200.

You should know immediately from that what 2 of the rolls will have to be.

There are only 4 possibililites for what the rest will be.

then you just have to work out how many ways each of those 4 sets of 6 numbers can be ordered.

Give it a go. :)

Melody Jun 9, 2022