Help how do you do this
There is a group of five children, where two of the children are twins. How many ways can I distribute 10 identical pieces of candy to the children, if the twins must get an equal amount of candy?
+20 Let's call the twins A and B, and the other three children C, D, and E. We can approach this problem by breaking it down into cases:
Case 1: A and B each get 1 piece of candy
In this case, we have 8 pieces of candy left to distribute to 5 children (A, B, C, D, E) without any restrictions. This is equivalent to distributing 8 identical pieces of candy to 5 children, which can be done in (8 + 5 - 1) choose (5 - 1) = 462 ways using stars and bars.
Case 2: A and B each get 2 pieces of candy
In this case, we have 6 pieces of candy left to distribute to 3 children (C, D, E) without any restrictions. This is equivalent to distributing 6 identical pieces of candy to 3 children, which can be done in (6 + 3 - 1) choose (3 - 1) = 21 ways using stars and bars.
So the total number of ways to distribute the candy is 462 + 21 = 483. My Sutter Online Login
