How many solutions are there to the equation

u + v + w + x + y + z = 18

where u, v, w, x, y, and z are nonnegative integers, and x is at most 10?

Guest Dec 14, 2022

#1**0 **

There are 656 solutions to this equation. This can be calculated using the stars and bars method. The equation can be rewritten as u + v + w + (x + y + z) = 18. This can be represented as a stars and bars problem, with 18 stars and 5 bars. The number of ways to arrange the stars and bars is equal to the number of solutions to the equation. The number of ways to arrange 18 stars and 5 bars is equal to the number of ways to choose 5 positions from 23 positions (18 stars + 5 bars). This can be calculated using the combination formula: C(23, 5) = 23! / (5! * 18!) = 23 * 22 * 21 * 20 * 19 / (5 * 4 * 3 * 2 * 1) = 23 * 22 * 21 * 20 * 19 / 120 = 656** **** ****Therefore****,**** there**** are**** 6****56**** solutions**** to**** the**** equation**** u**** +**** v**** +**** w**** +**** x**** +**** y**** +**** z**** =**** 18****,**** where**** u****,**** v****,**** w****,**** x****,**** y****,**** and**** z**** are**** non****negative**** integers****,**** and**** x**** is**** at**** most**** 10****.**

Guestonwebsite Dec 14, 2022

#2**0 **

By stars and bars, there are 5 bars and 18 stars, so there are \({23 \choose 5} = 33,649\)

But, this overcounts for the cases where x is greater than 10.

If x is 18, there are 0 stars and 4 bars which makes for \({4 \choose 4} = 1 \) case.

If x is 17, there are \({5 \choose 4} = 5\) cases

If x is 16, there are \({6 \choose 4} = 15\)

Notice a pattern?

This pattern will continue until \({11 \choose 4}\). Summing all these up gives us \(792\) cases.

So, there are \(33649 - 792 = \color{brown}\boxed{32,857} \) cases.

BuilderBoi Dec 14, 2022