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Find the number of positive integers that satisfy both the following conditions:
- Each digit is a 1 or a 2 or a 3
- The sum of the digits is 5

 May 27, 2024
 #1
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We can use constructive counting or casework to solve this problem. 

 

CASE 1

First, let's see all the two digit numbers that satisfy these conditions. 

We only have two, with 23 and 32. 


CASE 2

Now, let's check all the 3 digit numbers. 

We have 311, 131, 113, giving us 3. 

We also have 221, 212, and 122, giving us another 3. 

 

Case 3

4 digit number time! This is where it gets a bit complicated, but it's still not that bad. 

We have numbers with three 1s and one 2, which has 4 different possibilities. 

 

Case 4

Last case ! 5 digit numbers only have 1, with 11111. 

 

 

Now, we just have to add up all our cases, and we get 2+3+3+4+1 = 13. 

 

We have 13 numbers that satisfy the conditions. 

 

NOTICE: This problem didn't have a lot of cases, so it would be easy to count. Bigger and wider ranges would require permutations, which I really really dislike! :)

 

I hope I answered your question!

 

Thanks! :)

 May 27, 2024

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