I don't know how to count
In a regular decagon, the sides are to be colored with five different colors, so that sides are diametrically opposite have the same color. (Not all five colors need to be used.) One possible coloring is shown below.
In how many different ways can the sides of the decagon be colored? (Two colorings are considered identical if one can be rotated to form the other.)
There is really only 5 sides to be set because once you have one you automatically have its opposite.
Also roations are the same
so I think it is just
4! if all the colours are used that is 24 ways
If only 4 colours are used then I think it is 5C4 * 4C1 * 4!/2 or 5C4 * 4C1 *
1 = 5*4*12 = 240 ways
If only 3 colours are used and 3 are the same then maybe it is 5C3 * 3C1 * 4!/3! = 10 * 3 * 4 = 120ways
If 3 colours are used and 2 have 2 each then i'm going for 5C3 * 3C2 * 4!/(2!2!) = 10*3*6 = 180 ways
If 2 colours are used then you have to look at each senario that is 1:4, 2:3 splits
1:4, split 5C2*2 * 2C1 * 1 = 10 * 2 = 20 ways
2:3 split 5C2* 2 * 4C1 = 10* 2* 4 = 80 ways
If only 1 colour is used that there is only 1 possibility.
24+240+120+80+20+80+1 = 565
It is highly likely that one or more of these are wrong.