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Suppose that I have 6 different books,  2 of which are math books. In how many ways can I stack my 6 books on a shelf if I do not want the math books to be at the ends?

 Jun 15, 2021
 #1
avatar+33765 
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There are 4 slots for math books    12 ways to place them   (4 P 2)

    for each of those 12 placements the other books can be arranged  4 * 3 * 2 * 1 = 24 ways

 

24 * 12 = 288 ways

 Jun 15, 2021
 #2
avatar+114104 
+1

I was going to say that there are 4 choices for one end then 3 for the other end then 4! for the rest (assuming all the books are different)

 

So that is 4*3*4! = 12*24 = 288

 

Just as EP found  cool

 Jun 16, 2021

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