This is a counting problem plz help
Syd chooses two different primes, both of which are greater than 10 and multiplies them. The resulting product is less than How many different products could Syd have ended up with?
+941 Let's start by finding the prime numbers greater than 10 that Syd could have chosen. The prime numbers between 11 and 100 are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
Since Syd is choosing two different primes, he has 20 options for the first prime and 19 options for the second. The resulting products would be:
11 * 13 = 143
11 * 17 = 187
11 * 19 = 209
...
89 * 97 = 8613
So there are 20 * 19 = 380 different products that Syd could have ended up with.
