Using the digits 1, 2, 3, 4, 5, how many even three-digit numbers less than \(300\) can be formed if each digit can be used more than once?

You have 2 choices for the first digit [1 and 2] ==2

You have 5 choices for the 2nd digit [1, 2, 3, 4, 5]==5

You have 2 choices for the 3rd digit [2 and 4]==2

Total number of 3-digit permutations under 300 and all EVEN ==2 x 5 x 2 ==20 such permutations.